0.7^2+2(0.7)x+x^2=1

Solution for 0.7^2+2(0.7)x+x^2=1 equation:

0.7^2+2(0.7)x+x^2=1

We move all terms to the left:

0.7^2+2(0.7)x+x^2-(1)=0

determiningTheFunctionDomain
x^2+2(0.7)x-1+0.7^2=0

We add all the numbers together, and all the variables

x^2+2(0.7)x-0.51=0

We multiply parentheses

x^2+1.4x-0.51=0

a = 1; b = 1.4; c = -0.51;
Δ = b2-4ac
Δ = 1.42-4·1·(-0.51)
Δ = 4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{4}=2$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1.4)-2}{2*1}=\frac{-3.4}{2}
=-1+1/1.4285714285714
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1.4)+2}{2*1}=\frac{0.6}{2}
=0.6/2
$